E-views Essay Example | Topics and Well Written Essays - 2750 words

E-views - Essay Example dependent var 1946.249 S.E. of regression 455.4699   Ã‚  Ã‚  Ã‚  Akaike info criterion 15.33487 Sum squared resid 3526698.   Ã‚  Ã‚  Ã‚  Schwarz criterion 15.72491 Log likelihood -183.6859   Ã‚  Ã‚  Ã‚  Hannan-Quinn criter. 15.44305 F-statistic 60.17375   Ã‚  Ã‚  Ã‚  Durbin-Watson stat 1.916498 Prob(F-statistic) 0.000000 (a) The estimated equation is: Y = 148.220572044 - 1.28739451915*X1 + 1.80962162969*X2 + 0.59039598443*X3 - 21.4816857405*X4 + 5.61940285601*X5 - 14.51467253*X6 + 29.3602583452*X7 The interpretation of the estimated coefficients is provided below: Table 3: Coefficient values and their interpretation Coefficient Value Interpretation Coefficient 1 148.2206 This is the intercept. ... ase in the manhour requirement by approximately 0.60 hours per week Coefficient 5 -21.4817 for an increase of the common use area by an additional square feet will imply a reduction of the manhour requirement by 21 hours per month Coefficient 6 5.619403 If the number of building wings increases by one, the additional monthly manhour requirement rises by 5.61 Coefficient 7 -14.5147 for an increase of operational berthing capacity by an additional unit, the monthly manhour requirement falls by 14.51 Coefficient 8 29.36026 For every additional number of rooms, approximately 29.4 additional manhours per month become necessary (b) Testing for significances Here, n=25 and we test at the 95% level (0.05). The test is two sided. For these specifications, the critical value: . From the 4th column of table 2 we see that only the coefficients of X2, X4, X6 and X7 exceed the critical value (in absolute terms). Thus, these are the only variables that are found to be significant, i.e., the coeffic ients are statistically different from zero. It can be checked from the column of probabilities it is only these coefficients that have p-values less than 0.05. Therefore, the conclusion is that only the monthly number of check ins, common use area, operational berthing capacity and number of rooms have statistically significant effects on the predicted variable, the required manhours to run the establishment. Problem 2 The test of joint significance is an F test of the null hypothesis that all coefficients are equal to zero, i.e., the parameters are jointly insignificant. In Eviews this is equivalent to using the Wald test for testing the restriction: The 5% critical F-statistic value for one restriction and 17 degrees of freedom (n=25, k=8) is 4.451. Observe from table 2 that the computed